Question

a circular cycler track has a circumference of 314m with AB as one of his daimeter.A cyclist travellers from a to b along the circular path with velocity 15.7m/s.find the distance moved by cyclist and the diaplacement of cyclist if AB reprence north south direction

Answer 1

)distance travelled =  half of the circumference of circular path

              = 314/2

= 157m.

b)displacement of the cyclist is the diameter of circular path

 we know circumference = 3.14* d  where d is the diameter.

d = 314/3.14

  = 10m.

c) cyclist starts his race from rest so the initial velocity(u) is zero & the final velocity(v) is 15.7 

  average velocity = u+v/2

            = 15.7/2

            = 7.85m/s.

Answer 2

Hi ..

Hope this helps u!!