Question

A circular disc of mass 10kg and radius 0.2m is set into rotation about and an axis passing throug its centr and perpendicular to ots plane by applying torque 10 Nm calculat angular velocity of the disc that it will attain at end of 6 s from the rest

Answer 1

moment of inertia(I)=10×.04

=.4kgm^2

torque=I×a (a is angular acceleration)

a=.4/10

=.04m/s^2

initial angular velocity=0

a=.04

t=6

so,

W=0+.04×6. (W is final angular momentum)

=.24m/s

hope it helps you

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