a circular disc of mass M and radius R is in pure rolling on horizontal surface as shown. the velocity of its centre of mass is Vo. then the ration of net velocity of point a and point b will be??
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Answer:
hope it helps..
Explanation:
ω=Rv (rolling)
Angular momentum about origin =mvr⊥+Ioω
v⊥= distance perpendicular to velocity from origin
Io= Moment of inertia about point O (centre of mass of disk)
=m1ωR×R+2mR2ω
⇒23mR2ω (ω=∞)
=23mR2∞.
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