A circular disc of radius 0.1 m and mass 1 kg is rotating at the rate of 10 rps about its axis . Find the work that must be done to increase the rate of revolution to 20 rps
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Explanation as the object is moving in circular path PE is 0
So TE= KE
KE (1)=1/2*1*10*10
=50J
KE (2)=1/2*1*20*20
=200J
Therefore,work done =200-50=150J
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