Question

A circular disc of radius 20 cm, is cut from one edge of large circular disc of radius
50 cm, the shift of COM is
1) 6.7 cm
2) 5.7 cm
3) 3.2 cm
4) -3.2 cm​

Answer 1

Answer:

option (2) is correct ie. 5.7

Answer 2

Step-by-step explanation:

Given A circular disc of radius 20 cm, is cut from one edge of large circular disc of radius 50 cm, the shift of COM is

• Now we have a large circular disc and the radius is 50 cm. Now from the edge 20 cm is cut. So the centre will be 20 cm, 20 cm and outside 10 cm
• Now using negative mass concept we have,
•             So Density = mass / surface area
•                                = mass / π r^2
•                                 = mass / π (50)^2 x π x (0.2)^2 (let mass = m)
•                                 = - 4m / 25 (for small disc)
• Now for system of particle for centre of mass will be
•       Also origin is (0,0)
•                                      m1x1 + m2x2 / m1 + m2
•                      M (0) + (-4M)/25 (0.3) / M + (-4M/25) (0.3 since 20 + 10 = 30 cm = 0.3 m)
•                   So – 4M / 25 x 0.3 / 21 M / 25
•                     = - 1.2 / 21 m
•   So in cm we get – 1.2 / 21 x 100
•                            = 5.71 cm
• So shift will be in the x direction of centre of mass and y direction is unchanged.

Reference link will be

https://brainly.in/question/20337988

https://brainly.in/question/7128934