a circular disc rolls down on inclined plane a=? v=? t=?
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Answer:
we know that,
KE
Total
=KE
Transnational
+KE
Rotational
Let the disc(MR) has moved down a
height 'h' has velocity v and
angular w.
Than for pure Rolling
RW=V
KE
Total
=
2
1
mv
2
+
2
I
w
2
For disc, I=
2
1
mR
2
So, KE
Total
=
2
1
mv
2
+
2
1
(
2
mR
2
w
2
)=
4
3
mv
2
Fraction of total energy that is transnational
=
4
3
mv
2
2
1
mv
2
=
3
2
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