Question

a circular disc rolls down on inclined plane a=? v=? t=?​

Answer 1

Answer:

we know that,

KE

Total

=KE

Transnational

+KE

Rotational

Let the disc(MR) has moved down a

height 'h' has velocity v and

angular w.

Than for pure Rolling

RW=V

KE

Total

=

2

1

mv

2

+

2

I

w

2

For disc, I=

2

1

mR

2

So, KE

Total

=

2

1

mv

2

+

2

1

(

2

mR

2

w

2

)=

4

3

mv

2

Fraction of total energy that is transnational

=

4

3

mv

2

2

1

mv

2

=

3

2