Question

A circular disc with 1800 holes is rotating at 720 rpm. If a jet of air passes through the holes, the frequency of sound emitted is

Answer 1

frequency of emitted sound is 21600 Hz.

it is given that A circular disc with 1800 holes is rotating at 720 rpm. If a jet of air passes through the holes.

we have to find the frequency of emitted sound.

we know, number of holes in the disk determines the number of waves.

so number of waves = 1800

given, angular frequency, ω = 720 rpm

= 720/60 rev/s = 12 rev/s

now frequency = number of waves × angular frequency

= 1800 × 12 rev/s

= 21600 Hz

therefore, frequency of emitted sound is 21600 Hz.

Answer 2

Answer:

Explanation:number of waves = 1800

given, angular frequency, ω = 720 rpm

= 720/60 rev/s = 12 rev/s

now frequency = number of waves × angular frequency

= 1800 × 12 rev/s

= 21600 Hz