A circular field has a circumference of 260km. Three cyclists start together and can cycle 60km, 72km, 90km a day, around the field .After how many days will they meet again at a starting point.
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First, we will get how much time all three cyclists take to cover a circumference of 360 km
So, the time taken for cyclist1 = 360/48 = 7.5 days
So, the time taken for cyclist2 = 360/60 = 6 days
So, the time taken for cyclist3 = 360/72 = 5 days
Here, LCM of 7.5, 6, 5 = 30
So, they will meet after 30 days.
Now, in 30 days, first cyclist will travel = 30/7.5 = 4 rounds
In 30 days, second cyclist will travel = 30/6 = 5 rounds
In 30 days, third cyclist will travel = 30/5 = 6 rounds
So, after 30 days, all the 3 cyclists will meet at starting point.
So, the time taken for cyclist1 = 360/48 = 7.5 days
So, the time taken for cyclist2 = 360/60 = 6 days
So, the time taken for cyclist3 = 360/72 = 5 days
Here, LCM of 7.5, 6, 5 = 30
So, they will meet after 30 days.
Now, in 30 days, first cyclist will travel = 30/7.5 = 4 rounds
In 30 days, second cyclist will travel = 30/6 = 5 rounds
In 30 days, third cyclist will travel = 30/5 = 6 rounds
So, after 30 days, all the 3 cyclists will meet at starting point.
Answered by
0
First cyclist =60 km
Second cyclist = 72 km
Third cyclist = 90 km
All the three cyclist meets at a starting point :
LCM of 60, 72, 90
Second cyclist = 72 km
Third cyclist = 90 km
All the three cyclist meets at a starting point :
LCM of 60, 72, 90
6 60, 72, 90
3 10, 12, 15
5 10, 4, 5
2 2, 4, 1
1, 2, 1
LCM = 6x3x5x2x2=360 km
So after 360m run all the three cyclist meet together
oshoraa:
after 360 km
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