Question

A circular field of radius 30m has a circular path of width 3m inside its boundary . Find that area of the path
Pie 3.14

Answer 1

Answer:

Area of the path will be 537 m²

Step-by-step explanation:

Radius of the circular field, R = 30 m

Area of the circular field = πR² = 3.14 x 30² = 2826 m²

width of the path = 3 m

=> Radius of the circular field excluding the path, r = 30 - 3 = 27

=> Area of the circular field excluding the path = πr² = 3.14 x 27²

= 2289 m²

Hence Area of the path = Area of the outer circle - Area of the inner circle

= 2826 - 2289

= 537 m²

Hence area of the path will be 537 m²

Answer 2

Answer:

Area of the path(A)= 536.94m²

Explanation:

Radius of the circular field

(OA) = R = 30m

width of the path (w) = 3m

Radius of the inner circle

(OB) = r = R - w

= 30 - 3

= 27 m

Area of the path(A)

= πR²-πr²

= π(R²-r²)

= π(R+r)(R-r)

= 3.14×(30+27)(30-27)

= 3.14 × 57 × 3

= 536.94m²

Therefore,

Area of the path(A)= 536.94m²