Question

A circular fish pond has diameter 28m the pond is sourandad by concrete path 2.1m wide find the area of the path

Answer 1

Step by step explanation:

diameter of a Pond=28m

Therefore,. radius = 28/2 = 14m

$area \: of \: circular \: pond = \pi {r}^{2}$
=π × 14×14
= π × 196
= 22/7 × 196
= 22 × 28
=616 square .m.

Thickness of concrete surrounding=2.1m

joining the concrete surrounding to pond.
Therefore,
radias of new circle=16.1m

$area \: of \: new \: circle = \pi {r}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ = \pi \: {( 16.1)}^{2} m \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \pi \times 259.21 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 813.9194 {m}^{2}$
area of the path= area of New circle ―
area of the Pond
= 813.9194 ― 616
=197.9194 square.m