Question

A circular flexible current loop of radius R carrying current i is placed in an inward magnetic field B . if we spin the loop with angular speed ω, then tension in string ( assume the mass of the loop is m)

Answer 1

Answer:

is zero

Explanation:

hope it helps !!!

Answer 2

The tension in the string will be more than iBR.

We know that the force current carrying circular loop is radially outward direction by using the Fleming's Left hand rule.

∴ $F = iBl sin 90^0$

⇒ F = iBl

Here, let dF be the force for the small length of element dR

∴ dF = iBdR

Thus, for the whole circle, dF ≥ iBR

Thus, the tension in the string will be more than iBR

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