Question

A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower
bed is 66 m. What is the area of this path?

correct answer = 10 thanks
varified answer = 29 thanks​

Answer 1

Answer:

Given:-

Width of the path = 4 m

Diameter of the flower bed = 66 m

To find:-

The area of the path.

Solution:-

Diameter of the flower bed is 66 m.

So, Radius of the flower bed =diameter/2

= (66/2)m

= 33m.

Now, Area of flower bed = π r²

⟹ Area = 3.14 × (33)²

⟹Area = 3.14 × 1089.

⟹Area = 3419.49 m²

Now, Diameter of large circle

= Width of path + diameter of flower bed.

= ( 66 + 4)m

= 70m

So, Radius of large circle

= (diameter/ 2)

= (70/2)m

= 35 m.

Now, Area of large circle = π r²

➟Area = 3.14 × (35)²

➟Area = 3.14 × 1225.

➟Area = 3846.5

So, now Area of path

= Area of large circle - Area of flower bed

= 3846.5 - 3419.49

= 427.01 m² (ans)

Therefore, the area of the path is 427.01 m².

hope it helps you.....

Answer 2

Diameter of the circular flower bed=66m

∴ Radius of circular flower bed$(r)= \frac{66}{2} = 33$

∴ Radius of circular flower bed with 4 m wide path(R)=33+4=37m

According to the question,

Area of path=Area of bigger circle−Area of smaller circle

$=πR ^{2} −πr^{2} =π(R ^{2} −r^{2} )$

=3.14[(37+33)(37−33)]

=3.14×70×4

=879.20m²