A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path?
Answers
Answered by
9
Answer:
880m²
Explanation:
Given that :—
- r = 66m ÷ 2 = 33m
- R = (33m + 4m) ÷ 2 = 37m
To be found :—
- Area of the path ( ring-shaped )
Placing all the given information in the formula to find out the area of a ring , we get :—
A = π(R² - r²) , where ,
- A is the area of the ring ( area of the path )
- R² is the outer radius ( radius of the flower bed to the path )
- r² is the inner radius ( radius of the flower bed )
Solution :—
A = 22/7(37m × 3m - 33m × 33m)
= 22/7(1369m² - 1089m²)
= 22/7 × 280m²
= 880m²
Answered by
17
Given:
- A circular flower bed is surrounded by a path 4 m wide.
- The diameter of the flower bed is 66 m.
To Find:
- What is the area of this path?
Solution:
Concept: Here, It is said that the diameter of a circle is 66m and it is surrounded by a path of length 4m and we have to find the area of the path
We know that,
Now, let's find the area of the inner circle,
- Here,
➪ Diameter = 66m so,
➪ Radius = 66/2 = 33m
Substituting the values we get,
- Therefore area of the inner circle is 3419.46m²
Now, let's find the area of the outer circle,
- Here,
➪ Radius = 33m + 4m
➪ Radius = 37m
Substituting the values we get,
- Hence, the area of the other circle is 4298.66m²
Now, let's find the area of the path,
We know,
Applying the concept,
Hence,
- The area of the path is 879.2m²
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