English, asked by Anonymous, 1 month ago

A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path?​

Answers

Answered by idiot2006
9

Answer:

880m²

Explanation:

Given that :—

  • r = 66m ÷ 2 = 33m
  • R = (33m + 4m) ÷ 2 = 37m

To be found :—

  • Area of the path ( ring-shaped )

Placing all the given information in the formula to find out the area of a ring , we get :—

A = π(R² - r²) , where ,

  • A is the area of the ring ( area of the path )
  • R² is the outer radius ( radius of the flower bed to the path )
  • r² is the inner radius ( radius of the flower bed )

Solution :—

A = 22/7(37m × 3m - 33m × 33m)

= 22/7(1369m² - 1089m²)

= 22/7 × 280m²

= 880m²

Answered by Anonymous
17

Given:

  • A circular flower bed is surrounded by a path 4 m wide.
  • The diameter of the flower bed is 66 m.

To Find:

  • What is the area of this path?

Solution:

Concept: Here, It is said that the diameter of a circle is 66m and it is surrounded by a path of length 4m and we have to find the area of the path

We know that,

 \:  \:  \:  \:  \:  \star  \: \tt {\pink{ \boxed{ \tt{area \: of \: a \: circle = \pi {r}^{2} }}}}

 \\

Now, let's find the area of the inner circle,

  • Here,

➪ Diameter = 66m so,

➪  Radius = 66/2 = 33m

 \\

Substituting the values we get,

 \\

 \longrightarrow \tt \: area = \pi {r}^{2}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \\  \\ \longrightarrow \tt \: area  = 3.14 \times 33 \times 33 \\  \\  \\ \longrightarrow \tt \: area  = 3419.46 {m}^{2}  \:  \:  \:  \:  \:  \:  \:  \:  \:

  • Therefore area of the inner circle is 3419.46m²

 \\

Now, let's find the area of the outer circle,

  • Here,

➪ Radius = 33m + 4m

➪ Radius = 37m

 \\

Substituting the values we get,

 \\

\longrightarrow \tt \: area  = \pi {r}^{2}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \\  \\  \\  \longrightarrow \tt \: area  = 3.14 \times 37 \times 37 \\  \\  \\ \longrightarrow \tt \: area  = 4298.66 {m}^{2}  \:  \:  \:  \:  \:  \:  \:  \:  \:

  • Hence, the area of the other circle is 4298.66m²

 \\

Now, let's find the area of the path,

 \\

We know,

 \:  \:  \:  \:  \:  \star  \: \tt {\pink{ \boxed{ \tt{area \: of \: a \: path =  circle_{2} -  circle_{1}}}}}

 \\

Applying the concept,

 \\

\longrightarrow \tt \: area  \: of \: path =  circle_{2} - circle_{1} \\  \\  \\ \longrightarrow \tt \: area  \: of \: path = 4298.66 - 3419.46 \\  \\  \\ \longrightarrow \tt \: area  \: of \: path = { \boxed{ \tt{879.2 {m}^{2} }}} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

 \\

Hence,

  • The area of the path is 879.2m²

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