A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path? (π = 3.14)
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Answers
Answer:
Diameter of the circular flower bed=66m
∴ Radius of circular flower bed(r)=
2
66
=33m
∴ Radius of circular flower bed with 4 m wide path(R)=33+4=37m
According to the question,
Area of path=Area of bigger circle−Area of smaller circle
=πR
2
−πr
2
=π(R
2
−r
2
)
=π[(37)
2
−(33)
2
]
=3.14[(37+33)(37−33)] [∵a
2
−b
2
=(a+b)(a−b)]
=3.14×70×4
=879.20m
Answer:
Diameter of the circular flower bed=66m
∴ Radius of circular flower bed(r)= 66/2 =33m
∴ Radius of circular flower bed with 4 m wide path(R)=33+4=37m
According to the question,
Area of path=Area of bigger circle−Area of smaller circle
=πR² −πr² =π(R ² −r²)
=π[(37) ² −(33)²]
=3.14[(37+33)(37−33)] [∵a ² −b² =(a+b)(a−b)]
=3.14×70×4
=879.20m²
.
Therefore, the area of the path is 879.20m
2
.
Step-by-step explanation:
I hope it helped you