a circular flower bed is surrounded by a path 4m wide. the diameter of the flower bed is 66m . what is the area of path? (ĪĪ = 3. 14)
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2
Answer:
Answer
Diameter of the circular flower bed=66m
∴ Radius of circular flower bed(r)=
2
66
=33m
∴ Radius of circular flower bed with 4 m wide path(R)=33+4=37m
According to the question,
Area of path=Area of bigger circle−Area of smaller circle
=πR
2
−πr
2
=π(R
2
−r
2
)
=π[(37)
2
−(33)
2
]
=3.14[(37+33)(37−33)] [∵a
2
−b
2
=(a+b)(a−b)]
=3.14×70×4
=879.20m
2
.
Therefore, the area of the path is 879.20m
2
.
solution
Answered by
0
Diameter of the flower bed=66 m
Radius=33 m
area of the flower bed =πr²
=3.14×33×33
=3419.46
area of the whole field including the path=πr²
=3.14×37×37
=4298.66
Area of the path=4298.6666-3419.46
=879.2m²
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