Math, asked by sofia53, 1 year ago

a circular flower bed is surrounded by a path 4m wide the diameter of the flower bed is 66m what is the area of the path take pie =3.14

Answers

Answered by AJAYMAHICH
5
radius of flower bed= 66 / 2 = 33m


Radius of flower bed and path together = 33 + 4

= 37 m


Area of flower bed and path together

= 3.14 * 37 * 37
= 4298.66 m2

Area of flower bed

= 3.14 * 33 *33

= 3419.46 m2


Area of path

= Area of flower bed and path together - Area of flower bed
                      

= 4298.66 - 3419.46

= 879.20 m2
Answered by XxMissPaglixX
5

Given:-

Width of the path = 4 m

Diameter of the flower bed = 66 m

To find:-

The area of the path.

Solution:-

Diameter of the flower bed is 66 m.

So, Radius of the flower bed =diameter/2

= (66/2)m

= 33m.

Now, Area of flower bed =  π r²

⟹ Area = 3.14 × (33)²

⟹Area = 3.14 × 1089.

⟹Area = 3419.49 m²

Now, Diameter of large circle

= Width of path + diameter of flower bed.

= ( 66 + 4)m

= 70m

So, Radius of large circle

= (diameter/ 2)

= (70/2)m

= 35 m.

Now, Area of large circle =  π r²

➟Area = 3.14 × (35)²

➟Area = 3.14 × 1225.

➟Area = 3846.5

So, now Area of path

= Area of large circle - Area of flower bed

= 3846.5 - 3419.49

= 427.01 m² (ans)

Therefore, the area of the path is 427.01 m².

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