Question

A circular flower bed is surrounded by a path 5 M wide. the diameter of a flower bed is 65 M. what is the area of path?

Answer 1

Answer:

Diameter of flowerbed=65 m

Radius=65/2

Its area=(22/7)x(65/2)x(65/2)

Diameter of flowerbed+path=65+5+5=75 m

Radius=75/2

Its area=(22/7)x(75/2)x(75/2)

Area of path=Total area-Ar of flowerbed

={(22/7)x(75/2)x(75/2)}-{(22/7)x(65/2)x(65/2)}

=1100 sq m

Step-by-step explanation:

Answer 2

The area of path is 1100 sq.m.

Step-by-step explanation:

Diameter of flower bed = 65 m

Radius of flower bed = $\frac{65}{2}=32.5 m$

Width of path = 5 m

Outer radius = 32.5+5=37.5 m

Area of path = Outer path - Inner path

Area of path = $\pi R^2-\pi r^2 = \frac{22}{7} \times 37.5^2-\frac{22}{7} \times 32.5^2=1100 m^2$

Hence The area of path is 1100 sq.m.

#Learn more:

A circular flower bed is surrounded by a path 4m wide. The diameter of the flower bed is a circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66m what is the area of this path? Pie value is 3.14

https://brainly.in/question/2037460