A circular flower bed is surrounded by a path 5 m wide the diameter of flower bed is 65m what is the area of the path
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Given that:-
Diameter of the flower bed(d) = 66 m
∴ Radius of the flower bed (r1) = 33 m
So, the area of the flower bed (A1) = πr12
= 3.14 × 33 × 33
= 3419.46 m2
Also the width of road is 4 m
∴ Radius of the flower bed with road (r2) = (33 + 4) m
= 37 m
So the area of the flower bed with road (A2) = πr22
= 3.14 × 37 × 37
= 4298.66 m2
Hence the area of the road = (Area of the flower bed with road) – (Area of flower bed)
= A2 – A1
= 4298.66 × 3419.46 m2
= 879.20 m2
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Diameter of the flower bed(d) = 66 m
∴ Radius of the flower bed (r1) = 33 m
So, the area of the flower bed (A1) = πr12
= 3.14 × 33 × 33
= 3419.46 m2
Also the width of road is 4 m
∴ Radius of the flower bed with road (r2) = (33 + 4) m
= 37 m
So the area of the flower bed with road (A2) = πr22
= 3.14 × 37 × 37
= 4298.66 m2
Hence the area of the road = (Area of the flower bed with road) – (Area of flower bed)
= A2 – A1
= 4298.66 × 3419.46 m2
= 879.20 m2
Please mark as brainliest
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