A CIRCULAR FLOWER BED IS SURROUNDED BY A PATH 8M WIDE . the diameter of the flower bed is 62m.what is the area of this path
Answers
Answered by
2
Answer:
Sol:) Radius of flower bed = 33 m (Diameter/2=radius).... Radius of flower bed and path together = 33 + 4 = 37m. So, Area of flower bed (path together )= 3.14 × 37 × 37 = 4298.66 m2. Area of flower bed = 3.14 × 33 × 33 = 3419.46 m2 Area of path = Area of flower bed and path together − Area of flower bed = 4298.66 − 3419.46 = 879.20 m2
Hope this helps you...
please mark as brainlist answer.
Answered by
17
diameter of the flower bed is 62m.
then, radius=62/2m=31m
area of flower bed= pie r²
=22/7 × (31)²
=22/7 × 31 × 31m²
=21,142/7m²
radius of the whole field =(31+8)m=39m
area of the whole field,
=22/7 × (39)²
=33,462/7m²
therefore,
area of the path=(33462/7)‐(21142/7)
=(33462‐21142)/7
=12,320/7
=1,760m²
ANSWER:–
1,760m²
Similar questions