Math, asked by nehasariyamangal, 6 months ago

A CIRCULAR FLOWER BED IS SURROUNDED BY A PATH 8M WIDE . the diameter of the flower bed is 62m.what is the area of this path​

Answers

Answered by 2602alpha
2

Answer:

Sol:) Radius of flower bed = 33 m (Diameter/2=radius).... Radius of flower bed and path together = 33 + 4 = 37m. So, Area of flower bed (path together )= 3.14 × 37 × 37 = 4298.66 m2. Area of flower bed = 3.14 × 33 × 33 = 3419.46 m2 Area of path = Area of flower bed and path together − Area of flower bed = 4298.66 − 3419.46 = 879.20 m2

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Answered by smosan75
17

diameter of the flower bed is 62m.

then, radius=62/2m=31m

area of flower bed= pie r²

=22/7 × (31)²

=22/7 × 31 × 31m²

=21,142/7m²

radius of the whole field =(31+8)m=39m

area of the whole field,

=22/7 × (39)²

=33,462/7m²

therefore,

area of the path=(33462/7)‐(21142/7)

=(33462‐21142)/7

=12,320/7

=1,760m²

ANSWER:–

1,760m²

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