Question

A circular flower bed is surrounded externally by a path which is 2 m wide . the diameter of the flower bed is 36 m find the are of the path also calculate the cost of leveling of the path at rs 15 per m2​

Answer 1

Step-by-step explanation:

here the diameter of the flower bed is 36m so radius will be 18m (d=2r)

Now lets calculate the radius of the whole structure including the path.

the path is 2 m wide which means that the radius will increase by 2m if we include the path in our structure. So radius of whole structure=18+2=20

now area of the flower bed:

=πr²

=22/7 ×18²

=22/7 × 324

=1018.3

Area of whole structure =

=πr²

=22/7 × 20²

=22/7 × 400

=1257.1

now area of path =area of whole structure - area of flower bed

=1257.1 - 1018.3

=238.8

∴area of path = 238.8

cost of levelling path per meter = 15/2

total cost of levelling path=15/2 × 238.8

=₹1791