A circular. gale in a vertical wall has a diameter of 4.00 m and hinged along horizontal axis.
The water surface on the upstream sige is 10.00 m above the top of the gate and on the
Fowlistream side is 2.00 m below the top of the gate. Find the resultant force acting on the
Sate and is location.
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Answer:Solution: (a) The resultant force F, may be found by simply applying the hydrostatic
relation
3 F h A (9790 N/m )(3 1.5 m)(5 m 2 m) 440,550 N (a) CG 441 kN Ans.
(b) The horizontal force acts as though BC were vertical, thus hCG is halfway down from
C and acts on the projected area of BC.
F (9790)(4.5)(3 2) 264,330 N . (b) H 264 kN Ans
The vertical force is equal to the weight of fluid above BC,
F (9790)[(3)(4) (1/2)(4)(3)](2) 352,440 . (b) V 352 kNAns
The resultant is the same as part (a): F [(264)2 (352)2]
1/2 441 kN.
Step-by-step explanation:
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