A circular garden is surrounded by a path that is 2.5 m wide The radius of the garden is 30m .Kunal ran along the outer edge of the path (a) What was the distance Kunal ran if he ran around the path five times (b) Find the area of the path
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Answer:
Let R be radius of outer circle and r be radius of inner circle.
It has been given that 44 m is the circumference of outer circle, → 2лR = 44 m
22 2 x x R = 44 7 =>
44 22 7 2 x 7 x 44 2 × 22 R = = 7m
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It is given that circular path is 2 m wide. So, radius of inner circle r =R-2=7-2=
5 m
So, inner circumference of path = 2лr =
22 2 x x 5 = 31.42 m 7
Therefore,
Area of the path = area of outer circle - are
л(R² - ²)
= 2(72-52) = 7 22 7 x 24
= 75.43 m²
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Step-by-step explanation:
(a) 1020.50m
(b) 490.625m²
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