Math, asked by Neha99601, 6 months ago

A circular garden of radius 80 m has a pathway around and outside it of width 3 m find the cost of levelling the path at rupees 7.50 sq.m

Answers

Answered by Anonymous
15

Step-by-step explanation:

area of circular garden = πr^2

radius = 80m

area of circular garden = π(80)^2 = 6400π m^2

area of circular garden with pathway = π(R)^2

radius of circular garden with pathway = 80+3 = 83m

area of circular garden with pathway = π(83)^2 = 6889π m^2

Area of pathway = area of circular garden with pathway - area of circular garden

Area of pathway = 6889π - 6400π = 489π m^2 = 489 × 22/7 (π = 22/7)

= 1536.85 m^2

cost for per sq. m = ₹ 7.50

cost of levelling the path = 1536.85 × 7.50 =

₹ 11,526.375

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Answered by Anonymous
0

Answer:

hello mate here is your answer

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