Question

A circular grassy pot of land of diameter 42m has a path 3.5m wide running around it on the outside. Find the cost of gravelling the path at rs.4 per square metre​​

Answer 1

Answer:

2002rs

Step-by-step explanation:

Area of outer circle = inner radius +3.5 path widhe

42/2+3.5=21+3.5=24.5

Area of outer circle = πr^2

$\frac{22}{7} \times 24.5 \times 24.5 = 1886.5 {m}^{2}$

Area of inner cirle πr^2

$\frac{22}{7} \times 21 \times 21 = 1386 {m}^{2}$

Area of path = Area of outer cicle -Area of inner circle

$1886.5 - 1386 = 500.5 {m}^{2} \\ cost \: of \: 1 {m}^{2} graveling \: = 4rs \\ cost \: of \: 500.5 {m}^{2} \: graveling = 500.5 \times 4 = 2002rs$