Math, asked by nt8151, 1 year ago

A circular hall(big room) has a hemispherical roof.The greatest height is equal to the inner diameter.Find the area of the floor,given that the capacity of the hall is 48510 cubic meter

Answers

Answered by TPS
89
let the inner diameter = D
          inner radius = D/2 = r 
Greatest height = D
height of cylindrical part (h)= D-r = r
radius of cylindrical part = r
area of floor = πr²

volume = volume of cylindrical part + volume of hemispherical part
           = πr²h + 2/3 πr³
           = πr³ + 2/3 πr³

48510= \frac{5}{3}  \pi  r^{3}

⇒   r= \sqrt[3]{ \frac{48510*3}{5 \pi } }  = \sqrt[3]{9269.43} =21m

Area\ of\ floor= \pi  r^{2} = \pi *21^{2}=1386\ m^{2}

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Answered by biswaskumar3280
3

Step-by-step explanation:

here is ur answer

with step by step

is it understandable

area of floor = 1386m²

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