Question

a circular hole of diameter 2cm in a brass sheet is left at 300 K. what will be the diameter of this hole when the sheet is heated to 400 K? given a for brass is 2×10‐⁵K-¹​

Answer 1

Answer:

R = Ro( 1 + αΔt)

R = 0.02(1 +2 x 10^-5 x 100)

R = 0.02(1 + 0.002)

R = 0.02 X 1.002

R = 0.02004 cm

R = 2.004 cm

hope this helps love