Question

A circular hoop of radius 65.3 cm and mass 2.16 Kg is suspended on a horizontal nail.

(a) Find its frequency of oscillation for small displacement from equilibrium???

(b) What is the length of the equivalent simple pendulum​

Answer 1

Answer:

b) T=2*V(x/g). A comparison of this formula with that giving the period of a simple pendulum in terms of its length L, T=2*V (L/g), shows that the length of the equivalent simple pendulum equals the spring's elongation to its new equilibrium position....