Question

A circular loop has a resistance of 40 Ω. Two points P and Q of the loop, which are one quarter of the circumference apart are connected to a 24 V battery, having an internal resistance of 0.5 Ω. What is the current flowing through the battery.
(A) 0.5 A (B) 1A (C) 2A (D) 3A
vi) To find the

Answer 1

3A current flowing through the battery  

Explanation:

A circular loop has a resistance of 40 Ω.

Two points P and Q of the loop, which are one quarter of the circumference apart

Resistance of Each part  = (1/4) 40 = 10 Ω    &  (3/4) 40 = 30 Ω  

10 Ω ║  30 Ω  

1/R = 1/10  + 1/30

=> 1/R = (3 + 1)/30

=> R = 30/4

=> R = 7.5 Ω.

internal resistance of 0.5 Ω.

Total Resistance = 7.5 +  0.5 = 8  Ω

Voltage applied  = 24V

Current  = 24/8  = 3A

3A current flowing through the battery.

option D is correct

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