Question

A circular loop.is suspended in air as
shown in figure. When the loop is seen
from above, current flows clockwise
and when seen from below current
flows anticlockwise. This loop behaves
like a a magnet. The S pole of this
magnet in on
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Answer 1

Answer:

The magnetic field lines due to PQ inside the coil is directed into the plane of paper. As current in PQ is constantly increasing, flux through the loop is also constantly increasing. According to lenz's law, current will flow in the loop in such a direction to oppose the increase in the magnetic flux through the loop. Hence, magnetic field due to the induced current in the loop should be projected outside the paper. Hence, current should flow in the anti-clockwise direction as per the right hand rule. 

Explanation:

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Answer 2

A circular loop is suspended in air as shown in figure. once the loop is seen from on top of, current flows dextrorotatory and once seen from below current flows anticlockwise. This loop behaves sort of a a magnet. The S pole of this magnet ought to be on top of the plane .

• According to lenz's law, current can flow within the loop in such a direction to oppose the rise within the magnetic flux through the loop.
• Hence, flux thanks to the induced current within the loop ought to be projected outside the paper. Hence, current ought to flow within the anti-clockwise direction as per the proper hand rule.

• Clock rule: once we have a tendency to face the coil and current flows dextrorotatory then that finish can act as pole and another finish as pole.

• If current flows in anticlockwise then one finish forward observes are going to be pole and different pole.

• Clock rule: once we have a tendency to face the coil and current flows dextrorotatory then that finish can act as pole and another finish as pole.

• If current flows in anticlockwise then one finish forward observes are going to be pole and different pole.

• Since a current carrying circular loop behaves as a dipole whose magnetic moment's direction is perpendicular to the plane of the circular loop.

Therefore, once this dipole is replaced by equivalent magnet then the road change of integrity NS are going to be perpendicular to the plane of the loop.

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