A circular loop of 80 urns with radius 15.0 cm is perpendicular to a magnetic field of 0.52 T. How much induced voltage is created if it rotated in 0.20 s so that its face is parallel to the field?
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Answered by
0
Answer:
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Answered by
1
Answer:
Induced emf in the loop is given by
e=−B.
dt
dA
where A is the area of the loop.
e=−B.
dt
d
(πr
2
)=−Bπ2r
dt
dr
r=2 cm=2×10
−2
m
dr=2 mm=2×10
−3
m
dt=1s
e=−0.04×3.14×2×2×10
−2
×
1
2×10
−3
V
=0.32π×10
−5
V
=3.2π×10
−6
V
=3.2πμV.
Explanation:
When we close the switch, the current takes some time to grow in the circuit. Due to this growth of current, the flux increases; hence, an emf is induced. On the other hand, when we open the switch, there is no path for the current to flow; hence, it suddenly drops to zero. This rate of decrease of current is much greater than the rate of growth of current when the switch is closed. So, when the switch is opened, the induced emf is more.
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