Question

A circular loop of area 0.01 m² carrying current 10A is placed parallel to a magnetic field of intensity of
0.1 T.The torque(in N-m) acting on the loop is
[ ]
b) 0.8
c) 0.001
d) 0.01
a) 1.1
​

Answer 1

Answer:

0.01m

2

,I=10A,B=0.1T,θ=90

o

,sinθ=1

Now magnetic moment M =I×A

Torque, τ=

M

ˉ

×

B

ˉ

=MBsinθ

=IAB

=10×0.01×0.1=