Physics, asked by soldiershubhamp8ttas, 1 year ago

A circular loop of radius 5 cm carries a current of 0.5A . Calculate the magnitude of the magnetic field at its centre.

Answers

Answered by Anonymous
35
HEY BUDDY..!!!

HERE'S THE ANSWER..

_____________________

♠️We know magnetic field at centre of a ring is given by

✔️ B = u° × I / 2 × r

⏺️B is magnetic field = ?

⏺️I ( current following in ring ) = 5 A

⏺️r ( radius of ring ) = 5cm = 5 × 10^-2 m

⏺️u° ( magnetic permeability due to free space ) = 4 π × 10^-7 T m / A

♠️ B = u° × I / 2 × r

=> B = ( 4 π × 10^-7 × 5 ) / ( 2 × 10^-2 )

=> B = ( 20 π × 10^-7 ) ( 10 × 10^-2 )

=> B = ( 20 π × 10^-7 × 10 )

=> B = ( 2 π × 10^-5 ) T ✔️✔️

Or

=> B = ( 0.2 π ) G ✔️✔️

✔️As { 1 T = 10^4 G}


✔️G is Gauss

✔️T is Tesla
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Answered by Anonymous
11
B = nue not × I / 2 r

B = 4π×10^-7 × 5 / 2×0.05

B= 2π × 10^-6/0.1

B= 2π × 10^-5 T
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