Question

A circular loop of radius R carrying a current I is placed in uniform magnetic field B perpendicular to loop .the force on the loop is​

Answer 1

Answer:

2πBIR

Explanation:

Force on a current carrying conductor,

F=BILSinθ

where B=strength magnetic field in Tesla

I=current in Amperes

L=length of conductor in metres

θ=angle between conductor and magnetic field

from your question we have,

angle as 90,

current as I,

magnetic field as B,

and radius of conductor as R

we need to calculate the length of the loop which is simply the circumference

C=2πr

in this case = 2πR

putting all the variables into the formula

we get F=BI2πRSin90

since Sin90=1

then,

F=2πBIR