a circular park 42m in diameter has a path 3.5m wide running around it on outside . find the cost of gravelling path at 4 per Sq.m
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diameter of the inner circular Park =42m=21m=radius r
width of outer path =3.5m
radius of the outer path R =21+3.5=24.5m
area of the path A=PI(R+r)(R-r)
A=22/7 (24.5+21)(24.5-21)
A=22/7 45.5x3.5
A=22x45.5x0.5
A=500.5s.m
the cost of gravelling at the rate of Rs4 per Sq.m
=4x500.5
=Rs.2002.
width of outer path =3.5m
radius of the outer path R =21+3.5=24.5m
area of the path A=PI(R+r)(R-r)
A=22/7 (24.5+21)(24.5-21)
A=22/7 45.5x3.5
A=22x45.5x0.5
A=500.5s.m
the cost of gravelling at the rate of Rs4 per Sq.m
=4x500.5
=Rs.2002.
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