Question

A circular park has a path along its boundary of width 7 m. The diameter of the circular park  is 70 m. What is the area of this path? ​

Answer 1

Answer:

1386$m^{2}$

Step-by-step explanation:

diameter of the park is 70 m

Therefore, the radius of the park is 70/2 = 35m

The width of the path = 7 m

Area of the whole park = π$r^{2}$

                                      ⇒$\frac{22}{7}$ × $35^{2}$

                                      ⇒$\frac{22}{7}$× 35 × 35

                                      ⇒ 22 × 35 × 5

                                      ⇒ 3850 $m^{2}$

Radius of the park which inside the path area = 35 - 7 = 28 m

Area inside the path area= π$r^{2}$

                                         ⇒$\frac{22}{7}$ × 28 × 28

                                         ⇒ 22 × 28 × 4

                                         ⇒ 2464$m^{2}$

Area of the path = Area of the whole park - Area inside the path area

                           ⇒ 3850 - 2464

                           ⇒ 1386$m^{2}$