Question

A circular park has a path of uniform width around it.The difference between the outer and inner circumferences of the circular path is 132m.Find the width of circular path.​

Answer 1

Answer:

Width of circular path is 21m. It is the difference between their radii.

Step-by-step explanation:

2π(r-r')=132

44/7(r-r')=132.

Therefore, r-r'=132*7/44

=21.

Answer 2

Width of circular path$=21cm$

Step-by-step explanation:

Given,

Difference between outer and inner circumference of circular park is$=132cm$

Let ,outer radius be$=r_{2}cm$

       inner radius be$= r_{1}cm$

Circumference of circle$=2\Pi \times r$

Difference in circumference

$132=2\times \Pi \left ( r_{2} -r_{1}\right )$

$132=2\times 22/7\left ( r_{2}-r_{1} \right )$

$132\times 7/\left ( 2\times 22 \right )=\left ( r_{2}-r_{1} \right )$

$3\times 7=r_{2}-r_{1}$

$r_{2}-r_{1}=21cm$

Width of circular path $=21cm$

or

$r_{2}-r_{1}=21cm$