Question

A circular park has a path of uniform width around it. The difference between the outer and inner circumferences of the circular path is 132 m. Its width is
(a)20 m
(b)21 m
(c)22 m
(d)24 m

Answer 1

Answer:

The width of the circumference of a circle, (R - r) is 21 cm.

Among the given options option (b) 21 m is the correct answer.

Step-by-step explanation:

Given :  

Difference between the outer and inner circumference of the circular path = 132 cm

Let the outer radius of the circular path be ‘R’ and inner radius be ‘r’ and outer and inner circumference of the circular path be C1 & C2.

Circumference of a circle = 2πr

C1 - C2 = 132

2πR1 - 2πr = 132

2π(R - r) = 132

2 × 22/7 (R - r) = 132

44/7 × (R - r) = 132

(R - r) = 132 × 7/44

(R - r) = 3 × 7  

(R - r) = 21 cm

Width of the circumference of a circle, (R - r) = 21 cm

Hence, the width of the circumference of a circle, (R - r) is 21 cm.

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

Solution:

Let R and r are outer and inner

radius of a circular park.

width of the path(w) = R-r

According to the problem given,

The difference between the outer and inner circumferences of the circular path is 132 m.

$\boxed {circumference \: of \: a \: circle (C) = 2πr}$

2πR - 2πr = 132 m

=> 2π(R-r) = 132 m

=> 2×(22/7)×w = 132

=> w = (132 × 7 )/(2×22)

After cancellation, we get.

w = 21 m

Therefore,

Width of the path (w) = 21m

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