a circular Park of 28 diameter has been constructed a 3.5 metre circular track outside has been develop along the park using algebraic formula find the area of tractor round the park
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diameter of the park =d= 28m
radius(r) =d/2 =28/2 =14m
track width(w) =3.5m
radius of the track = R = r+w =14+3.5=17.5m
area of the track = πR²-πr²
= π(R²-r²)
=π(R+r)(R-r)
=22/7* (17.5+14)(17.5-14)
=22/7 * 31.5*3.5
=22*31.5*0.5
=346.5m²
radius(r) =d/2 =28/2 =14m
track width(w) =3.5m
radius of the track = R = r+w =14+3.5=17.5m
area of the track = πR²-πr²
= π(R²-r²)
=π(R+r)(R-r)
=22/7* (17.5+14)(17.5-14)
=22/7 * 31.5*3.5
=22*31.5*0.5
=346.5m²
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