A circular park of 28m diameter has been constructed. A 3.5m circular track outside has been
developed along the park. Using algebraic formulae, find the area of the track around the
park.
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Hi ,
Diameter of the
circular park(d) = 28m
radius of the park = r = d /2
r = 28/2 = 14m
Width of the track ( w ) = 3.5 m
Radius of the outer circle = R
R = r + w
R = 14 + 3.5
R = 17.5 m
Area of the track
= Area of the outer circle - area of
the inner circle
= πR² - πr²
= π ( R² - r² )
= π ( R + r ) ( R - r )
= π ( 17.5 + 14 ) ( 17.5 - 14 )
= ( 22 /7 ) × 31.5 × 3.5
= 22 × 31.5 × 0.5
= 346.5 Square meters
Area of the track = 346.5 sq m
I hope this helps you.
:)
Diameter of the
circular park(d) = 28m
radius of the park = r = d /2
r = 28/2 = 14m
Width of the track ( w ) = 3.5 m
Radius of the outer circle = R
R = r + w
R = 14 + 3.5
R = 17.5 m
Area of the track
= Area of the outer circle - area of
the inner circle
= πR² - πr²
= π ( R² - r² )
= π ( R + r ) ( R - r )
= π ( 17.5 + 14 ) ( 17.5 - 14 )
= ( 22 /7 ) × 31.5 × 3.5
= 22 × 31.5 × 0.5
= 346.5 Square meters
Area of the track = 346.5 sq m
I hope this helps you.
:)
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