A circular Park of 28m diameter has been constructed. A 3.5m circular track outside has been developed along the park. Using algebraic formulae, find the area of the track around the park.
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Hi ,
The diameter of the circular park
d = 28 m
Radius ( r ) = d/2
r = 28/2 = 14 m
If the circular track of width ( w ) =
3.5m outside has been developed
along the park then the radius of the
Outer circle
R = r + w
R = 14 + 3.5
R = 17.5m
Area of the circular track around the
park = area of outer circle - area of
inner circle
A = πR² - πr²
A = π( R² - r² )
A = π ( R + r ) ( R - r )
[ Since a² - b² = ( a + b ) ( a - b )]
A = (22/7) ( 17.5 + 14 )( 17.5 - 14 )
A = (22/7)(31.5)(3.5)
A = ( 22)(31.5)(0.5)
A = 346.5 square meters
I hope this helps you.
:)
The diameter of the circular park
d = 28 m
Radius ( r ) = d/2
r = 28/2 = 14 m
If the circular track of width ( w ) =
3.5m outside has been developed
along the park then the radius of the
Outer circle
R = r + w
R = 14 + 3.5
R = 17.5m
Area of the circular track around the
park = area of outer circle - area of
inner circle
A = πR² - πr²
A = π( R² - r² )
A = π ( R + r ) ( R - r )
[ Since a² - b² = ( a + b ) ( a - b )]
A = (22/7) ( 17.5 + 14 )( 17.5 - 14 )
A = (22/7)(31.5)(3.5)
A = ( 22)(31.5)(0.5)
A = 346.5 square meters
I hope this helps you.
:)
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