A circular park of 28m diameter has been constructed. A3.5m circular track outside has been developed along the park. Using algebraic formulae, find the area of the track around the park
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diameter of the park = 28m
radius of the park (r) = d/2 = 28/2= 14m
after circular track 3.5 m width developed
radius of the bigger circle = R = r+w =14+3.5 =17.5 m
area of the track = πR² - πr²
=π(R² - r²)
=π(R+r)(R - r)
=π(17.5 +14)(17.5 -14)
= 22/7 * 31.5 * 3.5
= 22 * 31.5 *0.5
=346.5m²
radius of the park (r) = d/2 = 28/2= 14m
after circular track 3.5 m width developed
radius of the bigger circle = R = r+w =14+3.5 =17.5 m
area of the track = πR² - πr²
=π(R² - r²)
=π(R+r)(R - r)
=π(17.5 +14)(17.5 -14)
= 22/7 * 31.5 * 3.5
= 22 * 31.5 *0.5
=346.5m²
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