Question

A circular Park of diameter 154 metres to foot path around it the length of the outer edge of the footpath is 506 M find the width of the footpath

Answer 1

Answer:

the width of the footpath is 22 m

Step-by-step explanation:

 A circular Park of diameter (2r) =154 m

so the radius of the circular park is (r) = 77m

therefore the circumfrence of the  circular park is =2πr m

                                                                                   =(2×22×77)/7 m

                                                                                    =484 m

the width of the footpath = (506 - 484)m

                                         =22 m

Answer 2

Dear Student,

◆ Answer -

Width of the footpath = 3.5 m.

● Explaination -

Inner radius of footpath is -

r = 154/2

r = 77 m

Let R be outer radius of footpath.

2πR = 506

R = 506 / (2×22/7)

R = 80.5 m

So width of the footpath is -

w = R - r

w = 80.5 - 77

w = 3.5 m

Hence, width of the footpath is 3.5 m.

Thanks dear. Hope this helps you...