Question

A circular park of radius 10 m is situated in a colony, Due to maintenance work done in the park, a triangular barricade is set upon points A, B & C around the work area so that visitors do not step on the area. Points A B & C are equidistant from each other and sit on the circumference of the park.

(1) The angle made by point A with the two other points B &

a) 30°

b) 45

c) 60

d) 90°​

Answer 1

Answer:

60°

Step-by-step explanation:

Given -

A triangular barricade is set up on points A, B and C.

All the three points are equidistant from each other.

Therefore -

The points A,B and C form a equilateral triangle.

So all the angles would be equal.

Let on angle be 'x'

Sum of all the angles of a triangle is 180°

x + x + x = 180 ( all angles are equal)

3x = 180

x = 180/3

= 60°