Question

a circular Park of radius 110 metre has a circular path of width 8m running along the boundary inside the park. find the area of the path. ​

Answer 1

Answer:

5328

Step-by-step explanation:

Area of path= area of exterior circle-area of interior circle

=pi*((R_square)-(r_square))

R=110(given)

r=110-8=102(As the width of the path is mentioned as 8m)

=π*(110²-102²)

=5328 metre square

Answer 2

The area of circular path=5330.29 square meter

Step-by-step explanation:

Radius of park=$r_1$=110m

Width of circular path=8m

Inner radius of park=$r_2$=110-8=102m

Area of circle=$\pi r^2$

Where $\pi=\frac{22}{7}$

Area of circular path=Area of outer circle-area of inner circle

Area of circular path=$\pi r^2_1-\pi r^2_2$

Area of circular path=$\frac{22}{7}(110)^2-\frac{22}{7}(102)^2=\frac{22}{7}((110)^2-(102)^2)$

Area of circular path=$\frac{22}{7}\times (12100-10404)=\frac{22}{7}\times 1696$

Area of circular path=5330.29 square meter

#Learns more:

https://brainly.in/question/14240541