a circular park of radius 15 m has a path of 10 m width around its outer side find the area of road. make sure that answer will come 1256 m
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Answered by
48
Area of circle=πr^2
=>Area of the circular park including the path=3.14×(15+25)^2
=3.14×25×25
=1962.5sq.m
Area of circular park=3.14×15×15
=706.5sq.m
Area of the path=(1962.5-706.5)sq.m
=1256sq.m
This is your answer.
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sanjaymishra8130:
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Answered by
7
Here, given that ,
Radius of circular park = 15mt.
therefore ,
ar. of circular park =πr²
= 3.14*15*15
= 1020.5 cm²
now, R of road outside the circle =( 15+10) mt.
= 25mt.
Ar. of the bigger circle = πr²
=3.14*25*25
= 1962.5 mt.²
now, ar. of road = ar. of bigger circle - ar. of circular park.
= ( 1962.5- 1020.5)mt.²
= 942 mt.²
Radius of circular park = 15mt.
therefore ,
ar. of circular park =πr²
= 3.14*15*15
= 1020.5 cm²
now, R of road outside the circle =( 15+10) mt.
= 25mt.
Ar. of the bigger circle = πr²
=3.14*25*25
= 1962.5 mt.²
now, ar. of road = ar. of bigger circle - ar. of circular park.
= ( 1962.5- 1020.5)mt.²
= 942 mt.²
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