A Circular park of radius 20 m has a pathway along its circumference. A man starts from A and walks along the Pathway to reach the diametrically opposite to B. Find his distance, displacement. If the man covers one-fourth of the circumference more and stops. What are the displacement and distance Covered by the man.
Answers
Answer:
(a)Displacement is given by the minimum distance between the initial and final positions of a body. In the given case, the cyclist comes to the starting point after cycling for 10 minutes. Hence, his net displacement is zero.
(b)Average velocity is given by the relation:
Average velocity = Net Displacement / Total time
Since the net displacement of the cyclist is zero, his average velocity will also be zero.
(c)Average speed of the cyclist is given by the relation:
Average speed = Total path length / Total time
Total path length =OP+PQ+QO
=1+
4
(2π1)
+1
=2+(π/2)
=3.570km
Time taken = 10 min = 10/60=1/6 hr
Average speed =3.570/(1/6)=21.42 km/h
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Answer:
(a)Displacement is given by the minimum distance between the initial and final positions of a body. In the given case, the cyclist comes to the starting point after cycling for 10 minutes. Hence, his net displacement is zero.
b)Average velocity is given by the relation:
Average velocity = Net Displacement / Total time
Since the net displacement of the cyclist is zero, his average velocity will also be zero.
(c)Average speed of the cyclist is given by the relation:
Average speed = Total path length / Total time
Total path length =OP+PQ+