A circular park of radius 20cm is situated in a colony.Three boys are sitting at equal distance on its boundary each having o toy telephone in his hands to talk to each other. Find the length of the string of each phone.
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AB, BC, AC are the strings of phones.
O is the centre and COP is a line passing through centre and making a 90 degree angle with AB. Now AP = BP = x.
And the line BO, bisects the angle ABC into two equal halves. So angle PBO is 30 degrees.
Now consider the right angled triangle PBO.
In this triangle, cos B = BP / BO
that is cos 30 = x / 20
that is x = 20 cos 30 = 17.32 m
Since AP = BP = x,
AB = 2x
AB = 34.64 m
So the length of each string is 34.64 m
P.S draw the diagram as mentioned above
O is the centre and COP is a line passing through centre and making a 90 degree angle with AB. Now AP = BP = x.
And the line BO, bisects the angle ABC into two equal halves. So angle PBO is 30 degrees.
Now consider the right angled triangle PBO.
In this triangle, cos B = BP / BO
that is cos 30 = x / 20
that is x = 20 cos 30 = 17.32 m
Since AP = BP = x,
AB = 2x
AB = 34.64 m
So the length of each string is 34.64 m
P.S draw the diagram as mentioned above
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