A circular park of radius 20m is situated in a colony. Three boys Ankur. Syed an
David are sitting at equal distance on its boundary each having a toy telephone
his hands to talk each other. Find the length of the string of each phone
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Answer:
Let Ankur be represented as A, Syed as S and David as D.
The boys are sitting at an equal distance.
Hence, △ASD is an equilateral triangle.
Let the radius of the circular park be r meters.
∴OS=r=20m.
Let the length of each side of △ASD be xmeters.
Draw AB⊥SD
∴SB=BD=21SD=2x m
In △ABS,∠B=90o
By Pythagoras theorem,
AS2=AB2+BS2
∴AB2=AS2−BS2=x2−(2x)2=43x2
∴AB=23x m
Now, AB=AO+OB
OB=AB−AO
OB=(23x−20) m
In △OBS,
OS2=OB
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