a circular park of radius 25 m has a road 5m wide running around it find the cost of metalling the road at the rate 18.20 per sq m
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radius of the circular Park=25m
width of the road =5m
radius of the road =25+5=30m
area of the road A =pi(30-25)(30+25)
A=22x5x55/2
A=6050/2
A=3025sq.m
Therefore the cost of metalling the road at the rate of 18.20 per Sq.m=3025x18.20
=Rs.55055
width of the road =5m
radius of the road =25+5=30m
area of the road A =pi(30-25)(30+25)
A=22x5x55/2
A=6050/2
A=3025sq.m
Therefore the cost of metalling the road at the rate of 18.20 per Sq.m=3025x18.20
=Rs.55055
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