Question

A circular park whose diameter is 35 m has a 1.4 m broad flower bed around it. What is the area
of the flower bed?​

Answer 1

The area of the flower  bed = 160.16 sq. m.

Explanation:

Given : The circular park whose diameter is 35 m.

Radius of park = r= $\dfrac{diameter}{2}=\dfrac{35}{2}=17.5\ m$

If it has a 1.4 m broad flower bed around it , then radius of the flower bed = R= 17.5m+1.4m = 18.9m

Area of flower bed = Area of flower bed including park - Area of park

= $\pi R^2-\pi r^2$

$=\pi(R^2-r^2)\\\\ = \pi(18.9^2-17.5^2)\\\\=\pi(357.21-306.25)\\\\=\dfrac{22}{7}(50.96)\\\\=160.16\ m^2$

Hence, the area of the flower bed = 160.16 sq. m.

# Learn more :

A circular flower bed is surrounded by a path 2 m wide. The diameter of the flower bed is 32 m. What is the area of this path ?

https://brainly.in/question/2397781

Answer 2

Answer:

The area of the flower bed = 160.16 sq. m.

Step-by-step explanation:

Explanation:

Given : The circular park whose diameter is 35 m.

Radius of park = r= \dfrac{diameter}{2}=\dfrac{35}{2}=17.5\ m

2

diameter

=

2

35

=17.5 m

If it has a 1.4 m broad flower bed around it , then radius of the flower bed = R= 17.5m+1.4m = 18.9m

Area of flower bed = Area of flower bed including park - Area of park

= \pi R^2-\pi r^2πR

2

−πr

2

\begin{gathered}=\pi(R^2-r^2)\\\\ = \pi(18.9^2-17.5^2)\\\\=\pi(357.21-306.25)\\\\=\dfrac{22}{7}(50.96)\\\\=160.16\ m^2\end{gathered}

=π(R

2

−r

2

)

=π(18.9

2

−17.5

2

)

=π(357.21−306.25)

=

7

22

(50.96)

=160.16 m

2

Hence, the area of the flower bed = 160.16 sq. m.